programming c++

Đã cho một số n in tổng của tất cả các số chẵn từ 1 đến n trong C++

 

Sum of first 20 Even numbers is: 420
9
                 Sum of first n even numbers = n * [n + 1].
5 
                 Sum of first n even numbers = n * [n + 1].
6
Sum of first 20 Even numbers is: 420
4 
                 Sum of first n even numbers = n * [n + 1].
8

                 Sum of first n even numbers = n * [n + 1].
9
Sum of first n terms of an A.P.[Arithmetic Progression]
= [n/2] * [2*a + [n-1]*d].....[i]
where, a is the first term of the series and d is
the difference between the adjacent terms of the series.

Here, a = 2, d = 2, applying these values to eq.[i], we get
Sum = [n/2] * [2*2 + [n-1]*2]
    = [n/2] * [4 + 2*n - 2]
    = [n/2] * [2*n + 2]
    = n * [n + 1]
0

 

                 Sum of first n even numbers = n * [n + 1].
9
Sum of first n terms of an A.P.[Arithmetic Progression]
= [n/2] * [2*a + [n-1]*d].....[i]
where, a is the first term of the series and d is
the difference between the adjacent terms of the series.

Here, a = 2, d = 2, applying these values to eq.[i], we get
Sum = [n/2] * [2*2 + [n-1]*2]
    = [n/2] * [4 + 2*n - 2]
    = [n/2] * [2*n + 2]
    = n * [n + 1]
2

                 Sum of first n even numbers = n * [n + 1].
9
Sum of first n terms of an A.P.[Arithmetic Progression]
= [n/2] * [2*a + [n-1]*d].....[i]
where, a is the first term of the series and d is
the difference between the adjacent terms of the series.

Here, a = 2, d = 2, applying these values to eq.[i], we get
Sum = [n/2] * [2*2 + [n-1]*2]
    = [n/2] * [4 + 2*n - 2]
    = [n/2] * [2*n + 2]
    = n * [n + 1]
4

Sum of first 20 Even numbers is: 420
9
Sum of first n terms of an A.P.[Arithmetic Progression]
= [n/2] * [2*a + [n-1]*d].....[i]
where, a is the first term of the series and d is
the difference between the adjacent terms of the series.

Here, a = 2, d = 2, applying these values to eq.[i], we get
Sum = [n/2] * [2*2 + [n-1]*2]
    = [n/2] * [4 + 2*n - 2]
    = [n/2] * [2*n + 2]
    = n * [n + 1]
6

 

Sum of first 20 Even numbers is: 420
9
Sum of first n terms of an A.P.[Arithmetic Progression]
= [n/2] * [2*a + [n-1]*d].....[i]
where, a is the first term of the series and d is
the difference between the adjacent terms of the series.

Here, a = 2, d = 2, applying these values to eq.[i], we get
Sum = [n/2] * [2*2 + [n-1]*2]
    = [n/2] * [4 + 2*n - 2]
    = [n/2] * [2*n + 2]
    = n * [n + 1]
8

Sum of first 20 Even numbers is: 420
9
Sum of first 20 Even numbers is: 420
0 
Sum of first 20 Even numbers is: 420
1

Sum of first n terms of an A.P.[Arithmetic Progression]
= [n/2] * [2*a + [n-1]*d].....[i]
where, a is the first term of the series and d is
the difference between the adjacent terms of the series.

Here, a = 2, d = 2, applying these values to eq.[i], we get
Sum = [n/2] * [2*2 + [n-1]*2]
    = [n/2] * [4 + 2*n - 2]
    = [n/2] * [2*n + 2]
    = n * [n + 1]
6

 

Sum of first 20 Even numbers is: 420
3

Sum of first 20 Even numbers is: 420
4 
Sum of first 20 Even numbers is: 420
5

Sum of first 20 Even numbers is: 420
8

Sum of first 20 Even numbers is: 420
9
Sum of first 20 Even numbers is: 420
4 
Sum of first 20 Even numbers is: 420
9

Sum of first 20 Even numbers is: 420
9
Sum of first 20 Even numbers is: 420
1____02 
Sum of first 20 Even numbers is: 420
3

Sum of first 20 Even numbers is: 420
4
Sum of first 20 Even numbers is: 420
5
Sum of first 20 Even numbers is: 420
6 
Sum of first 20 Even numbers is: 420
7

Sum of first 20 Even numbers is: 420
9
Sum of first 20 Even numbers is: 420
0 
                 Sum of first n even numbers = n * [n + 1].
610

Sum of first n terms of an A.P.[Arithmetic Progression]
= [n/2] * [2*a + [n-1]*d].....[i]
where, a is the first term of the series and d is
the difference between the adjacent terms of the series.

Here, a = 2, d = 2, applying these values to eq.[i], we get
Sum = [n/2] * [2*2 + [n-1]*2]
    = [n/2] * [4 + 2*n - 2]
    = [n/2] * [2*n + 2]
    = n * [n + 1]
6

Java




                 Sum of first n even numbers = n * [n + 1].
612

                 Sum of first n even numbers = n * [n + 1].
613

                 Sum of first n even numbers = n * [n + 1].
614 
                 Sum of first n even numbers = n * [n + 1].
615

                 Sum of first n even numbers = n * [n + 1].
614 
                 Sum of first n even numbers = n * [n + 1].
617

 

                 Sum of first n even numbers = n * [n + 1].
618 
                 Sum of first n even numbers = n * [n + 1].
619 
                 Sum of first n even numbers = n * [n + 1].
700

Sum of first 20 Even numbers is: 420
9

Sum of first 20 Even numbers is: 420
9
Sum of first 20 Even numbers is: 420
2

Sum of first 20 Even numbers is: 420
9
                 Sum of first n even numbers = n * [n + 1].
70

Sum of first 20 Even numbers is: 420
9
                 Sum of first n even numbers = n * [n + 1].
707 
Sum of first 20 Even numbers is: 420
4 
Sum of first 20 Even numbers is: 420
5
Sum of first 20 Even numbers is: 420
4 
Sum of first 20 Even numbers is: 420
7

Sum of first 20 Even numbers is: 420
9
Sum of first 20 Even numbers is: 420
8

                 Sum of first n even numbers = n * [n + 1].
9
Sum of first 20 Even numbers is: 420
4 
                 Sum of first n even numbers = n * [n + 1].
736
                 Sum of first n even numbers = n * [n + 1].
737
                 Sum of first n even numbers = n * [n + 1].
738
                 Sum of first n even numbers = n * [n + 1].
739
                 Sum of first n even numbers = n * [n + 1].
770

 

                 Sum of first n even numbers = n * [n + 1].
9
                 Sum of first n even numbers = n * [n + 1].
3

                 Sum of first n even numbers = n * [n + 1].
9
                 Sum of first n even numbers = n * [n + 1].
5 
                 Sum of first n even numbers = n * [n + 1].
6
Sum of first 20 Even numbers is: 420
4 
                 Sum of first n even numbers = n * [n + 1].
777
                 Sum of first n even numbers = n * [n + 1].
778
                 Sum of first n even numbers = n * [n + 1].
779

Sum of first 20 Even numbers is: 420
00
Sum of first n terms of an A.P.[Arithmetic Progression]
= [n/2] * [2*a + [n-1]*d].....[i]
where, a is the first term of the series and d is
the difference between the adjacent terms of the series.

Here, a = 2, d = 2, applying these values to eq.[i], we get
Sum = [n/2] * [2*2 + [n-1]*2]
    = [n/2] * [4 + 2*n - 2]
    = [n/2] * [2*n + 2]
    = n * [n + 1]
0

 

Sum of first 20 Even numbers is: 420
00
Sum of first n terms of an A.P.[Arithmetic Progression]
= [n/2] * [2*a + [n-1]*d].....[i]
where, a is the first term of the series and d is
the difference between the adjacent terms of the series.

Here, a = 2, d = 2, applying these values to eq.[i], we get
Sum = [n/2] * [2*2 + [n-1]*2]
    = [n/2] * [4 + 2*n - 2]
    = [n/2] * [2*n + 2]
    = n * [n + 1]
2

Sum of first 20 Even numbers is: 420
00
Sum of first 20 Even numbers is: 420
05
                 Sum of first n even numbers = n * [n + 1].
737
                 Sum of first n even numbers = n * [n + 1].
770

                 Sum of first n even numbers = n * [n + 1].
9
Sum of first n terms of an A.P.[Arithmetic Progression]
= [n/2] * [2*a + [n-1]*d].....[i]
where, a is the first term of the series and d is
the difference between the adjacent terms of the series.

Here, a = 2, d = 2, applying these values to eq.[i], we get
Sum = [n/2] * [2*2 + [n-1]*2]
    = [n/2] * [4 + 2*n - 2]
    = [n/2] * [2*n + 2]
    = n * [n + 1]
6

 

                 Sum of first n even numbers = n * [n + 1].
9
Sum of first n terms of an A.P.[Arithmetic Progression]
= [n/2] * [2*a + [n-1]*d].....[i]
where, a is the first term of the series and d is
the difference between the adjacent terms of the series.

Here, a = 2, d = 2, applying these values to eq.[i], we get
Sum = [n/2] * [2*2 + [n-1]*2]
    = [n/2] * [4 + 2*n - 2]
    = [n/2] * [2*n + 2]
    = n * [n + 1]
8

                 Sum of first n even numbers = n * [n + 1].
9
Sum of first 20 Even numbers is: 420
0 
Sum of first 20 Even numbers is: 420
14

Sum of first 20 Even numbers is: 420
9
Sum of first n terms of an A.P.[Arithmetic Progression]
= [n/2] * [2*a + [n-1]*d].....[i]
where, a is the first term of the series and d is
the difference between the adjacent terms of the series.

Here, a = 2, d = 2, applying these values to eq.[i], we get
Sum = [n/2] * [2*2 + [n-1]*2]
    = [n/2] * [4 + 2*n - 2]
    = [n/2] * [2*n + 2]
    = n * [n + 1]
6

Sum of first 20 Even numbers is: 420
9

Sum of first 20 Even numbers is: 420
9
Sum of first 20 Even numbers is: 420
19

Sum of first 20 Even numbers is: 420
9
                 Sum of first n even numbers = n * [n + 1].
618 
                 Sum of first n even numbers = n * [n + 1].
707 
Sum of first 20 Even numbers is: 420
23 
Sum of first 20 Even numbers is: 420
24

Sum of first 20 Even numbers is: 420
9
Sum of first 20 Even numbers is: 420
8

                 Sum of first n even numbers = n * [n + 1].
9
Sum of first 20 Even numbers is: 420
4 
Sum of first 20 Even numbers is: 420
29
Sum of first 20 Even numbers is: 420
30
                 Sum of first n even numbers = n * [n + 1].
770

                 Sum of first n even numbers = n * [n + 1].
9
Sum of first 20 Even numbers is: 420
33____02 
Sum of first 20 Even numbers is: 420
35

________ 036 ________ 06 ________ 038

Sum of first 20 Even numbers is: 420
36
Sum of first 20 Even numbers is: 420
40

Sum of first 20 Even numbers is: 420
9
Sum of first n terms of an A.P.[Arithmetic Progression]
= [n/2] * [2*a + [n-1]*d].....[i]
where, a is the first term of the series and d is
the difference between the adjacent terms of the series.

Here, a = 2, d = 2, applying these values to eq.[i], we get
Sum = [n/2] * [2*2 + [n-1]*2]
    = [n/2] * [4 + 2*n - 2]
    = [n/2] * [2*n + 2]
    = n * [n + 1]
6

 

Sum of first n terms of an A.P.[Arithmetic Progression]
= [n/2] * [2*a + [n-1]*d].....[i]
where, a is the first term of the series and d is
the difference between the adjacent terms of the series.

Here, a = 2, d = 2, applying these values to eq.[i], we get
Sum = [n/2] * [2*2 + [n-1]*2]
    = [n/2] * [4 + 2*n - 2]
    = [n/2] * [2*n + 2]
    = n * [n + 1]
6

 

Sum of first 20 Even numbers is: 420
44

Python3




Sum of first 20 Even numbers is: 420
45

Sum of first 20 Even numbers is: 420
46

Sum of first 20 Even numbers is: 420
9

Sum of first 20 Even numbers is: 420
48

Sum of first 20 Even numbers is: 420
46

Sum of first 20 Even numbers is: 420
50 
Sum of first 20 Even numbers is: 420
51

Sum of first 20 Even numbers is: 420
9
Sum of first 20 Even numbers is: 420
53
Sum of first 20 Even numbers is: 420
54 
                 Sum of first n even numbers = n * [n + 1].
737

Sum of first 20 Even numbers is: 420
9
Sum of first 20 Even numbers is: 420
57 
Sum of first 20 Even numbers is: 420
54 
                 Sum of first n even numbers = n * [n + 1].
739

Sum of first 20 Even numbers is: 420
9
Sum of first 20 Even numbers is: 420
61
Sum of first 20 Even numbers is: 420
54 
                 Sum of first n even numbers = n * [n + 1].
778

Sum of first 20 Even numbers is: 420
9

Sum of first 20 Even numbers is: 420
9
Sum of first 20 Even numbers is: 420
66

Sum of first 20 Even numbers is: 420
9
Sum of first 20 Even numbers is: 420
68 
Sum of first 20 Even numbers is: 420
69______054 
Sum of first 20 Even numbers is: 420
71

                 Sum of first n even numbers = n * [n + 1].
9
Sum of first 20 Even numbers is: 420
57 
Sum of first 20 Even numbers is: 420
38
Sum of first 20 Even numbers is: 420
54 
Sum of first 20 Even numbers is: 420
53

                 Sum of first n even numbers = n * [n + 1].
9

                 Sum of first n even numbers = n * [n + 1].
9
Sum of first 20 Even numbers is: 420
79

                 Sum of first n even numbers = n * [n + 1].
9
Sum of first 20 Even numbers is: 420
53____038
Sum of first 20 Even numbers is: 420
54 
                 Sum of first n even numbers = n * [n + 1].
737

                 Sum of first n even numbers = n * [n + 1].
9
Sum of first 20 Even numbers is: 420
61
Sum of first 20 Even numbers is: 420
54 
Sum of first 20 Even numbers is: 420
61
Sum of first 20 Even numbers is: 420
38 
                 Sum of first n even numbers = n * [n + 1].
778

Sum of first 20 Even numbers is: 420
9
Sum of first 20 Even numbers is: 420
0 
Sum of first 20 Even numbers is: 420
57

 

Sum of first 20 Even numbers is: 420
94

Sum of first 20 Even numbers is: 420
95
Sum of first 20 Even numbers is: 420
54 
Sum of first 20 Even numbers is: 420
30

Sum of first 20 Even numbers is: 420
98
                 Sum of first n even numbers = n * [n + 1].
6
                 Sum of first n even numbers = n * [n + 1].
00
                 Sum of first n even numbers = n * [n + 1].
01
                 Sum of first n even numbers = n * [n + 1].
02
                 Sum of first n even numbers = n * [n + 1].
03

                 Sum of first n even numbers = n * [n + 1].
04
                 Sum of first n even numbers = n * [n + 1].
05

 

                 Sum of first n even numbers = n * [n + 1].
06

C#




                 Sum of first n even numbers = n * [n + 1].
07

                 Sum of first n even numbers = n * [n + 1].
613

                 Sum of first n even numbers = n * [n + 1].
77 
                 Sum of first n even numbers = n * [n + 1].
10

 

                 Sum of first n even numbers = n * [n + 1].
618 
                 Sum of first n even numbers = n * [n + 1].
619 
                 Sum of first n even numbers = n * [n + 1].
13

 

Sum of first 20 Even numbers is: 420
9
Sum of first 20 Even numbers is: 420
2

Sum of first 20 Even numbers is: 420
9
                 Sum of first n even numbers = n * [n + 1].
70

Sum of first 20 Even numbers is: 420
9
                 Sum of first n even numbers = n * [n + 1].
707 
Sum of first 20 Even numbers is: 420
4 
Sum of first 20 Even numbers is: 420
5
Sum of first 20 Even numbers is: 420
4 
Sum of first 20 Even numbers is: 420
7

Sum of first 20 Even numbers is: 420
9
Sum of first 20 Even numbers is: 420
8

                 Sum of first n even numbers = n * [n + 1].
9
Sum of first 20 Even numbers is: 420
4 
                 Sum of first n even numbers = n * [n + 1].
1

 

                 Sum of first n even numbers = n * [n + 1].
9
                 Sum of first n even numbers = n * [n + 1].
3

                 Sum of first n even numbers = n * [n + 1].
9
                 Sum of first n even numbers = n * [n + 1].
5 
                 Sum of first n even numbers = n * [n + 1].
6
Sum of first 20 Even numbers is: 420
4 
                 Sum of first n even numbers = n * [n + 1].
8

Sum of first 20 Even numbers is: 420
00
Sum of first n terms of an A.P.[Arithmetic Progression]
= [n/2] * [2*a + [n-1]*d].....[i]
where, a is the first term of the series and d is
the difference between the adjacent terms of the series.

Here, a = 2, d = 2, applying these values to eq.[i], we get
Sum = [n/2] * [2*2 + [n-1]*2]
    = [n/2] * [4 + 2*n - 2]
    = [n/2] * [2*n + 2]
    = n * [n + 1]
0

 

Sum of first 20 Even numbers is: 420
00
Sum of first n terms of an A.P.[Arithmetic Progression]
= [n/2] * [2*a + [n-1]*d].....[i]
where, a is the first term of the series and d is
the difference between the adjacent terms of the series.

Here, a = 2, d = 2, applying these values to eq.[i], we get
Sum = [n/2] * [2*2 + [n-1]*2]
    = [n/2] * [4 + 2*n - 2]
    = [n/2] * [2*n + 2]
    = n * [n + 1]
2

Sum of first 20 Even numbers is: 420
00
Sum of first n terms of an A.P.[Arithmetic Progression]
= [n/2] * [2*a + [n-1]*d].....[i]
where, a is the first term of the series and d is
the difference between the adjacent terms of the series.

Here, a = 2, d = 2, applying these values to eq.[i], we get
Sum = [n/2] * [2*2 + [n-1]*2]
    = [n/2] * [4 + 2*n - 2]
    = [n/2] * [2*n + 2]
    = n * [n + 1]
4

                 Sum of first n even numbers = n * [n + 1].
9
Sum of first n terms of an A.P.[Arithmetic Progression]
= [n/2] * [2*a + [n-1]*d].....[i]
where, a is the first term of the series and d is
the difference between the adjacent terms of the series.

Here, a = 2, d = 2, applying these values to eq.[i], we get
Sum = [n/2] * [2*2 + [n-1]*2]
    = [n/2] * [4 + 2*n - 2]
    = [n/2] * [2*n + 2]
    = n * [n + 1]
6

 

                 Sum of first n even numbers = n * [n + 1].
9
Sum of first n terms of an A.P.[Arithmetic Progression]
= [n/2] * [2*a + [n-1]*d].....[i]
where, a is the first term of the series and d is
the difference between the adjacent terms of the series.

Here, a = 2, d = 2, applying these values to eq.[i], we get
Sum = [n/2] * [2*2 + [n-1]*2]
    = [n/2] * [4 + 2*n - 2]
    = [n/2] * [2*n + 2]
    = n * [n + 1]
8

                 Sum of first n even numbers = n * [n + 1].
9
Sum of first 20 Even numbers is: 420
0 
Sum of first 20 Even numbers is: 420
1

Sum of first 20 Even numbers is: 420
9
Sum of first n terms of an A.P.[Arithmetic Progression]
= [n/2] * [2*a + [n-1]*d].....[i]
where, a is the first term of the series and d is
the difference between the adjacent terms of the series.

Here, a = 2, d = 2, applying these values to eq.[i], we get
Sum = [n/2] * [2*2 + [n-1]*2]
    = [n/2] * [4 + 2*n - 2]
    = [n/2] * [2*n + 2]
    = n * [n + 1]
6

 

Sum of first 20 Even numbers is: 420
9
Sum of first 20 Even numbers is: 420
19

Sum of first 20 Even numbers is: 420
9
                 Sum of first n even numbers = n * [n + 1].
618 
                 Sum of first n even numbers = n * [n + 1].
707 
Sum of first 20 Even numbers is: 420
23 
                 Sum of first n even numbers = n * [n + 1].
57

Sum of first 20 Even numbers is: 420
9
Sum of first 20 Even numbers is: 420
8

                 Sum of first n even numbers = n * [n + 1].
9
Sum of first 20 Even numbers is: 420
4 
Sum of first 20 Even numbers is: 420
9

                 Sum of first n even numbers = n * [n + 1].
9

                 Sum of first n even numbers = n * [n + 1].
9
                 Sum of first n even numbers = n * [n + 1].
65
Sum of first 20 Even numbers is: 420
2 
                 Sum of first n even numbers = n * [n + 1].
67

Sum of first 20 Even numbers is: 420
4
Sum of first 20 Even numbers is: 420
38
Sum of first 20 Even numbers is: 420
6 
                 Sum of first n even numbers = n * [n + 1].
71

Sum of first 20 Even numbers is: 420
9
Sum of first n terms of an A.P.[Arithmetic Progression]
= [n/2] * [2*a + [n-1]*d].....[i]
where, a is the first term of the series and d is
the difference between the adjacent terms of the series.

Here, a = 2, d = 2, applying these values to eq.[i], we get
Sum = [n/2] * [2*2 + [n-1]*2]
    = [n/2] * [4 + 2*n - 2]
    = [n/2] * [2*n + 2]
    = n * [n + 1]
6

Sum of first n terms of an A.P.[Arithmetic Progression]
= [n/2] * [2*a + [n-1]*d].....[i]
where, a is the first term of the series and d is
the difference between the adjacent terms of the series.

Here, a = 2, d = 2, applying these values to eq.[i], we get
Sum = [n/2] * [2*2 + [n-1]*2]
    = [n/2] * [4 + 2*n - 2]
    = [n/2] * [2*n + 2]
    = n * [n + 1]
6

 

                 Sum of first n even numbers = n * [n + 1].
75

PHP




                 Sum of first n even numbers = n * [n + 1].
76

                 Sum of first n even numbers = n * [n + 1].
77

                 Sum of first n even numbers = n * [n + 1].
70

 

Sum of first 20 Even numbers is: 420
2

                 Sum of first n even numbers = n * [n + 1].
70

                 Sum of first n even numbers = n * [n + 1].
81 
Sum of first 20 Even numbers is: 420
5____183
                 Sum of first n even numbers = n * [n + 1].
84

Sum of first 20 Even numbers is: 420
8

Sum of first 20 Even numbers is: 420
9
                 Sum of first n even numbers = n * [n + 1].
87 
                 Sum of first n even numbers = n * [n + 1].
88

Sum of first 20 Even numbers is: 420
9
                 Sum of first n even numbers = n * [n + 1].
90 
                 Sum of first n even numbers = n * [n + 1].
91

 

Sum of first 20 Even numbers is: 420
9
                 Sum of first n even numbers = n * [n + 1].
3

Sum of first 20 Even numbers is: 420
9
                 Sum of first n even numbers = n * [n + 1].
5 
                 Sum of first n even numbers = n * [n + 1].
6
                 Sum of first n even numbers = n * [n + 1].
97 
                 Sum of first n even numbers = n * [n + 1].
98
                 Sum of first n even numbers = n * [n + 1].
97 
Sum of first n terms of an A.P.[Arithmetic Progression]
= [n/2] * [2*a + [n-1]*d].....[i]
where, a is the first term of the series and d is
the difference between the adjacent terms of the series.

Here, a = 2, d = 2, applying these values to eq.[i], we get
Sum = [n/2] * [2*2 + [n-1]*2]
    = [n/2] * [4 + 2*n - 2]
    = [n/2] * [2*n + 2]
    = n * [n + 1]
00
                 Sum of first n even numbers = n * [n + 1].
83
                 Sum of first n even numbers = n * [n + 1].
770
                 Sum of first n even numbers = n * [n + 1].
97
Sum of first n terms of an A.P.[Arithmetic Progression]
= [n/2] * [2*a + [n-1]*d].....[i]
where, a is the first term of the series and d is
the difference between the adjacent terms of the series.

Here, a = 2, d = 2, applying these values to eq.[i], we get
Sum = [n/2] * [2*2 + [n-1]*2]
    = [n/2] * [4 + 2*n - 2]
    = [n/2] * [2*n + 2]
    = n * [n + 1]
04

                 Sum of first n even numbers = n * [n + 1].
9
                 Sum of first n even numbers = n * [n + 1].
90 
Sum of first n terms of an A.P.[Arithmetic Progression]
= [n/2] * [2*a + [n-1]*d].....[i]
where, a is the first term of the series and d is
the difference between the adjacent terms of the series.

Here, a = 2, d = 2, applying these values to eq.[i], we get
Sum = [n/2] * [2*2 + [n-1]*2]
    = [n/2] * [4 + 2*n - 2]
    = [n/2] * [2*n + 2]
    = n * [n + 1]
07
                 Sum of first n even numbers = n * [n + 1].
87
                 Sum of first n even numbers = n * [n + 1].
770

 

                 Sum of first n even numbers = n * [n + 1].
9
Sum of first n terms of an A.P.[Arithmetic Progression]
= [n/2] * [2*a + [n-1]*d].....[i]
where, a is the first term of the series and d is
the difference between the adjacent terms of the series.

Here, a = 2, d = 2, applying these values to eq.[i], we get
Sum = [n/2] * [2*2 + [n-1]*2]
    = [n/2] * [4 + 2*n - 2]
    = [n/2] * [2*n + 2]
    = n * [n + 1]
2

                 Sum of first n even numbers = n * [n + 1].
9
                 Sum of first n even numbers = n * [n + 1].
87 
Sum of first n terms of an A.P.[Arithmetic Progression]
= [n/2] * [2*a + [n-1]*d].....[i]
where, a is the first term of the series and d is
the difference between the adjacent terms of the series.

Here, a = 2, d = 2, applying these values to eq.[i], we get
Sum = [n/2] * [2*2 + [n-1]*2]
    = [n/2] * [4 + 2*n - 2]
    = [n/2] * [2*n + 2]
    = n * [n + 1]
14

Sum of first 20 Even numbers is: 420
9
Sum of first n terms of an A.P.[Arithmetic Progression]
= [n/2] * [2*a + [n-1]*d].....[i]
where, a is the first term of the series and d is
the difference between the adjacent terms of the series.

Here, a = 2, d = 2, applying these values to eq.[i], we get
Sum = [n/2] * [2*2 + [n-1]*2]
    = [n/2] * [4 + 2*n - 2]
    = [n/2] * [2*n + 2]
    = n * [n + 1]
6

 

Sum of first 20 Even numbers is: 420
9
Sum of first n terms of an A.P.[Arithmetic Progression]
= [n/2] * [2*a + [n-1]*d].....[i]
where, a is the first term of the series and d is
the difference between the adjacent terms of the series.

Here, a = 2, d = 2, applying these values to eq.[i], we get
Sum = [n/2] * [2*2 + [n-1]*2]
    = [n/2] * [4 + 2*n - 2]
    = [n/2] * [2*n + 2]
    = n * [n + 1]
8

Sum of first 20 Even numbers is: 420
9
Sum of first 20 Even numbers is: 420
0 
                 Sum of first n even numbers = n * [n + 1].
6
Sum of first 20 Even numbers is: 420
4
                 Sum of first n even numbers = n * [n + 1].
7311
                 Sum of first n even numbers = n * [n + 1].
7312______2737
                 Sum of first n even numbers = n * [n + 1].
84
Sum of first 20 Even numbers is: 420
01 
                 Sum of first n even numbers = n * [n + 1].
6
                 Sum of first n even numbers = n * [n + 1].
737 
Sum of first 20 Even numbers is: 420
38 
                 Sum of first n even numbers = n * [n + 1].
7319

Làm cách nào để in tổng các số chẵn trong C?

Chương trình. Viết chương trình tìm tổng các số chẵn bằng ngôn ngữ C. .
#include .
int chính []
int i, n, tổng=0;
printf["Nhập số bất kỳ. "];
scanf["%d", &n];
for[i=2; i

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