Find the least number which when divided by 12, 27 and 35 leaves 6 as a remainder

Find the least number which when divided by 12, 18, 24 and 30 leaves 4 as remainder in each case, but when divided by 7 leaves no remainder.

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SSC CGL Tier 2 Quant Previous Paper 3 (Held On: 18 November 2020)

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  1. 366
  2. 634
  3. 384
  4. 364

Answer (Detailed Solution Below)

Option 4 : 364

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15 Questions 15 Marks 9 Mins

Concept Used-

The least number which is divisible by several numbers is the LCM of such numbers.

Calculation-

The least number which is divisible by 12, 18, 24 and 30 = LCM of 12, 18, 24 and 30

⇒ 360

Now the least number which leaves remainder as 4 when divided by 12, 18, 24 and 30 = 360 + 4

⇒ 364

Now, 364 is divisible by 7.

∴ 364 is the required number.

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Find the least number which divided by 27, 35, 45 and 49 leaves the remainder 6 in each case?

Solution(By Examveda Team)

ANSWER = 6621
The least number which is divide by 27, 35, 45, 49 is their LCM.
27 = 3 * 3 * 3
35 = 5 * 7
45 = 3 * 3 * 5
49 = 7 * 7
So their LCM = 3 * 3 * 3 * 5 * 7 * 7 = 6615
Now just add 6 to 6615, to get the required number.
Required number = 6615 + 6 = 6621

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Solution

The correct option is C 151To find the least number which is divisible by 12, 16 ,24 and 36, we need to find L.C.M. of these numbers. 212,16,24,3626,8,12,1823,4,6,923,2,3,933,1,3,931,1,1,31,1,1,1 L.C.M. of 12, 16, 24, 36 =2×2×2×2×3×3=144 Least Number which when divided by 12, 16 ,24 and 36 leaves a remainder 7 in each case =144+7=151

What is the least number which when divided by 12 21 and 35 leaves remainder 6?

What will be the least number which when divided by 12 21 and 35 leaves a remainder 6 in each caseAns = 426.

What is the least number which when divided by 24 28 and 35 leaves 3 as remainder in each case?

What is the least number which when divided by 24, 28 and 35, leaves 3 as remainder in each case? Explanation: L.C.M of 24,28 adn 35 is 840. So the required number is 840 + 3 = 843.

What is the smallest number which when divided by 12 15 18 and 27 leaves remainder of 8 11 14 and 23 respectively?

Answer: The number is 536.

What is the least number which when divided by 12 15 20 leaves remainder 4?

∴ Required least such number is 544.