Answer
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Hint: In this question it is given that the probability of winning a game is 0.7. Now if we take E as an event then we can say P probability of winning the event is 0.7. So P=0.7. Now the probability of losing the game will be Q. and we know P+Q = 1. So with the help of this equation we’ll solve the problem. We’ll substitute the value of P and will find the value of Q. Q is the probability of losing the game. So Q’s value will be the answer.
Complete step-by-step
solution:
We know the sum of probability of an event happening and not happening is 1.
Here happening an event or winning the game is P.
It is given that $P = 0.7$
And not happening an event or losing an event is Q
Now we need to find the probability of losing the game
So we can write $P + Q = 1$
$0.7 + Q = 1 \\
\Rightarrow Q = 1 - 0.7 \\
\Rightarrow = 0.3 $
So the probability of losing the game is 0.3.
Note: Whenever you get a question of happening an event and not happening an event always take the probability of both the case and make the sum as 1. Because the event of winning a game and losing a game is always 1. Now just put the value and calculate the result. This way you’ll get the answer.
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It is given that the probability of winning a game is 0.7. What is the probability of losing the game? a 0.8 b 0.3 c 0.35 d 0.15
Solution
ANSWER:
[b] 0.3
Explanation:
Let E be the event of winning the game.
Then,
P[E] = 0.7
P[not E] = P[losing the game] = 1 − P[E] ⇒ 1 − 0.7 = 0.3
For any event E, P[E] + P[not E] = 1
Let probability of winning a game = P[E] = 0.7
∴ P[winning a game] + P[losing a game] = 1
⇒ P[losing a game] = 1 − 0.7
= 0.3
Thus, the probability of losing a game is 0.3.
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Text Solution
0.30.70.50
Answer : A
Solution : Let E be the event of winning the game.
Then, P[E ] = 0.7.
Probability of losing the game = ` 1-P[E ] = [1-0.7] = 0.3`.
Answer
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