The system kx y 2 and 6x 2y 3 has a unique solution when *

Correct Answer = (d) k ≠ 3

The given equations are 

kx – y – 2 = 0 ………(i) 

6x – 2y – 3 = 0 ……..(ii) 

Here, a1 = k, b1 = -1, c1 = -2, a2 = 6, b2 = -2 and c2 = -3. 

For the given system to have a unique solution, we must have 

The given system is
kx – y – 2 = 0                   ……(i)
6x – 2y – 3 = 0                 ……(ii)
Here, `a_1 = k, b_1 = -1, c_1 = -2, a_2 = 6, b_2 = -2 and c_2 = -3`
For the system, to have a unique solution, we must have
`(a_1)/(a_2) ≠ (b_1)/(b_2)`
`⇒ k/6 ≠ (−1)/(−2) = 1/2`
⇒ k ≠ 3
Hence, k ≠ 3.

When the system of equation has a unique solution the system is?

Systems of equations can be classified by the number of solutions. If a system has at least one solution, it is said to be consistent . If a consistent system has exactly one solution, it is independent .

What is the value of k if the system of equations kx y 2 and 6x 2y 3 have infinitely many solutions?

∴ For unique solution of system of equations, k=3,4.

For what value of k equation has unique solution?

So, the given of equations system will have a unique solution, if k=3.

What type of system has a unique solution?

An independent system has exactly one solution pair (x,y) . The point where the two lines intersect is the only solution.