Two dice are rolled together find the probability of getting a sum as a multiple of 3
n(s) = 36 i.e. Show (1,1)(1,2)(1,3)(1,4)(1,5)(1,6) (2,1)(2,2)(2,3)(2,4)(2,5)(2,6) (3,1)(3,2)(3,3)(3,4)(3,5)(3,6) (4,1)(4,2)(4,3)(4,4)(4,5)(4,6) (5,1)(5,2)(5,3)(5,4)(5,5)(5,6) (6,1)(6,2)(6,3)(6,4)(6,5)(6,6)} Event = {multiple of 3 as a sum} ∴ P(E) = `"n(E)"/"n(S)" = 12/36 = 1/3`. $\begingroup$ What is the probability that the sum of $2$ dice rolls is a multiple of $3$? What about for $3$ dice rolls? For $n$ dice rolls? So I have the first part of this solution worked out by writing out all the combinations of $2$ dice rolls (I won't write them here). There are $6^2=36$ total and the following multiples of $3$ are rolled: $$3\rightarrow2 ways$$$$6\rightarrow5ways$$$$9\rightarrow4ways$$$$12\rightarrow1way$$So adding up all the ways over the total rolls is the probability:$$\frac{2+5+4+1}{6^2}=\frac{12}{36}=\frac{1}{3}=0.33$$The second part and the general solution is what trips me up. I know there are $6^3$ possible rolls for $3$ dice, and we're now including the multiples $15$ and $18$, but how do I figure out how many ways there are to roll each multiple without counting all $216$ possibilities? How would I apply this to a general solution with $n$ dice? asked May 6, 2016 at 2:26
$\endgroup$ $\begingroup$ It is always $\frac{1}{3}$. To see this, roll the first $n-1$ dice. Now add the last die, which will make the sum divisible by 3 exactly $\frac{1}{3}$ of the time. answered May 6, 2016 at 2:32
$\endgroup$ 1 Answer Verified
Hint: Calculate the number of possible outcomes for throwing two dice. Calculate the number of favourable outcomes for each of the cases. Use the fact that the probability of any event is the ratio of the number of favourable outcomes and the number of possible outcomes to calculate the probability of each of the events.Complete step-by-step solution -
We observe that the possible values of prime numbers when two digits on the dice are added are 2, 3, 5, 7, and 11.
The possible values of multiples of 3 as a sum of digits on dice are 3, 6, 9, and 12. Try out challenging quizzes on this topic Take me there! What is the probability that the sum of two dice is a multiple of 3?We know that the number of possible outcomes is 36. Thus, the probability of getting multiples of 3 as a sum of digits on dice is =1236=13.
What is the probability of rolling a multiple of 3 on a dice?If it is a standard fair 6 sided die, the probability of rolling a multiple of 3 is (1/3). This is because all six numbers (1,2,3,4,5,6) are equally likely and two of the six 3 and 6 are multiples of three. Probability is the number of favorable outcomes divided by the total number of outcomes.
What is the probability of getting a multiple of 2 on one dice and multiple of 3 on the other dice?Total number of possible outcomes of sample space = 36. P (Getting multiple of 2 on one dice and multiple of 3 on other dice)=16. ∴The probability of getting multiple of 2 on one dice and multiple of 3 on other dice is 16.
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