What is the number of 3 digit odd numbers formed by using the digits 1 2 3 4 5 6 if repetition of digits is allowed?
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 How many 3-digit numbers can be formed from the digits 1, 2, 3, 4 and 5 assuming that repetition of the digits is allowed. Number of digits available = 5 Number of places for the digits = 3. Number of ways in which place (x) can be filled = 5 m = 5 Number of ways in which place (y) can be filled = 5 (∵ Repetition is allowed) n = 5 Number of ways in which place (z) can be filled = 5 (∵ Repetition is allowed) p = 5 ∴ By fundamental principle of counting, the number of 3-digit numbers formed. = m x n x p = 5 x 5 x 5 = 125 458 Views Given 5 flags of different colours, how many different signals can be generated if each signal requires use of 2 flags, one below the other? Number of ways of finding a flag for place 1 = 5 Number of remaining flags = 4 Number of ways of finding a flag for place 2 to complete the signal = 4 ∴ By fundamental principle of counting, the number of signals generated = 991 Views How many 3-digit numbers can be formed from the digits 1, 2, 3, 4 and 5 assuming that repetition of the digits is not allowed. Number of ways in which place (x) can be filled = 5 m = 5 Number of ways in which place (y) can be filled = 4 (∵ Repetition is not allowed) n = 4 Number of ways in which place (z) can be filled = 3 (∵ Repetition is not allowed) p = 3 ∴ By fundamental principle of counting, the total number of 3 digit numbers formed = m x n x p = 5 x 4 x 3 = 60. 526 Views A coin is tossed 3 times and the outcomes are recorded. How many possible outcomes are there?
Event 1: A coin is tossed and the outcomes recorded. Number of outcomes Event 2: The coin is tossed again and the outcomes recorded. Number of outcomes Event 3: The coin is tossed third time and the outcomes recorded. Number of outcomes ∴ By fundamental principle of counting, the total number of outcomes recorded = 548 Views How many 3-digit odd numbers can be formed from the digits 1,2,3,4,5,6 if:(a) the digits can be repeated (b) the digits cannot be repeated?(a) Number of digits available = 6 Number of places [(x), (y) and (z)] for them = 3 Repetition is allowed and the 3-digit numbers formed are odd Number of ways in which box (x) can be filled = 3 (by 1, 3 or 5 as the numbers formed are to be odd) Number of ways of filling box (y) = 6 (∴ Repetition is allowed) Number of ways of filling box (z) = 6 (∵ Repetition is allowed) ∴ Total number of 3-digit odd numbers formed = m x n x p = 3 x 6 x 6 = 108 (b) Number of ways of filling box (x) = 3 (only odd numbers are to be in this box ) Number of ways of filling box (y) = 5 (∵ Repetition is not allowed) Number of ways of filling box (z) = 4 (∵ Repetition is not allowed) ∴ Total number of 3-digit odd numbers formed = m x n x p = 3 x 5 x 4 = 60. 231 Views How many 3 digits odd numbers can be formed from 4 digits 1 2 3 4 )? While I repetition not allowed II repetition allowed?So there are 3 ways of filling the unit's place. As repetition of digits is not allowed, the ten's place can be filled in 5 ways with any of the remaining 5-digts and the hundred's place can be filled in 4 ways by the remaining 4-digits. So, Required number of three-digit odd numbers = 3 × 5 × 4 = 60.
How many three digits numbers can be formed using the digits 1 2 3 4 5 if digits can be repeated?There are 504 different 3-digit numbers which can be formed from numbers 1, 2, 3, 4, 5, 6, 7, 8, and 9 if no repetition is allowed.
How many three digit odd numbers can be formed using the digits 1 2 4 and 6 if repetition of digits is not allowed?Hence, by the fundamental principle of multiplication, the required number of odd numbers `= (3xx6xx6) = 108. ` How many 3How many 3-digit numbers can be formed from the digits 1, 2, 3, 4 and 5 assuming that repetition of the digits is not allowed. = m x n x p = 5 x 4 x 3 = 60. How many 3-digit numbers can be formed from the digits 1, 2, 3, 4 and 5 assuming that repetition of the digits is allowed. Number of places for the digits = 3.
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