Find the smallest natural number that we need to divide 500 with to make it a perfect cube
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A number is a perfect cube only when each factor in the prime factorization is grouped in triples. Using this concept, the smallest number can be identified. (i) 81 81 = 3 × 3 × 3 × 3 = 33 × 3 Here, the prime factor 3 is not grouped as a triplet. Hence, we divide 81 by 3, so that the obtained number becomes a perfect cube. Thus, 81 ÷ 3 = 27 = 33 is a perfect cube. Hence the smallest number by which 81 should be divided to make a perfect cube is 3. (ii) 128 128 = 2 × 2 × 2 × 2 × 2 × 2 × 2 = 23 × 23 × 2 Here, the prime factor 2 is not grouped as a triplet. Hence, we divide 128 by 2, so that the obtained number becomes a perfect cube. Thus, 128 ÷ 2 = 64 = 43 is a perfect cube. Hence the smallest number by which 128 should be divided to make a perfect cube is 2. (iii) 135 135 = 3 × 3 × 3 × 5 = 33 × 5 Here, the prime factor 5 is not a triplet. Hence, we divide 135 by 5, so that the obtained number becomes a perfect cube. 135 ÷ 5 = 27 = 33 is a perfect cube. Hence the smallest number by which 135 should be divided to make a perfect cube is 5. (iv) 192 192 = 2 × 2 × 2 × 2 × 2 × 2 × 3 = 23 × 23 × 3 Here, the prime factor 3 is not grouped as a triplet. Hence, we divide 192 by 3, so that the obtained number becomes a perfect cube. 192 ÷ 3 = 64 = 43 is a perfect cube Hence the smallest number by which 192 should be divided to make a perfect cube is 3. (v) 704 704 = 2 × 2 × 2 × 2 × 2 × 2 × 11 = 23 × 23 × 11 Here, the prime factor 11 is not grouped as a triplet. Hence, we divide 704 by 11, so that the obtained number becomes a perfect cube. Thus, 704 ÷ 11 = 64 = 43 is a perfect cube Hence the smallest number by which 704 should be divided to make a perfect cube is 11. ☛ Check: NCERT Solutions for Class 8 Maths Chapter 7 Video Solution: Find the smallest number by which each of the following numbers must be divided to obtain a perfect cube (i) 81 (ii) 128 (iii) 135 (iv) 192 (v) 704NCERT Solutions for Class 8 Maths Chapter 7 Exercise 7.1 Question 3 Summary: The smallest number by which each of the following numbers must be divided to obtain a perfect cube (i) 81 (ii) 128 (iii) 135 (iv) 192 (v) 704 are (i) 3, (ii) 2, (iii) 5, (iv) 3, and (v) 11 ☛ Related Questions:
The smallest natural number by which 1296 be divided to get a perfect cube is _________Answer Verified Hint: Here in this question we have to determine by which number the given number 1296 is divided such that it will be a perfect cube. Usually a prime factorization method is used to determine the cube root of a number, so the same method is implemented here also. On finding the prime factors of a number, then we can determine the smallest number which 1296 can be divided. Complete step by step solution: Note: We can verify the answer. On dividing the number 1296 by 6. The quotient will be 216. Using the prime factorization method we determine the factors.
What is the smallest number by which 500 must be divided to make a perfect cube?Wow! The only factor that doesn't occur in a group of 3 is 2. So, we would add one more factor of 2 to get 2 * 2 * 2 * 5 * 5 * 5 = 1000 which happens to be 10 cubed. So, the answer to your question is 2.
What should be added to 500 to make it a perfect cube?The smallest number 12 is added to 500 make it is a perfect cube.
IS 500 a perfect cube number?Is 500 a Perfect Cube? The number 500 on prime factorization gives 2 × 2 × 5 × 5 × 5. Here, the prime factor 2 is not in the power of 3. Therefore the cube root of 500 is irrational, hence 500 is not a perfect cube.
What is the smallest number by which 500 may be multiplied to get a perfect square?500 is multiplied by 5 to get a perfect square .
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