How many different ways can the letter of the word COMPUTER be arranged so that vowels always come together?

In how many different ways can the letters of the word TRAINER be arranged so that the vowels always come together?A. 1440B. 120C. 720D. 360

Answer

How many different ways can the letter of the word COMPUTER be arranged so that vowels always come together?
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Hint: To solve this problem we have to know about the concept of permutations and combinations. But here a simple concept is used. In any given word, the number of ways we can arrange the word by jumbling the letters is the number of letters present in the word factorial. Here factorial of any number is the product of that number and all the numbers less than that number till 1.
$ \Rightarrow n! = n(n - 1)(n - 2).......1$

Complete step by step answer:
Given the word TRAINER, we have to arrange the letters of the word in such a way that all the vowels in the word TRAINER should be together.
The number of vowels in the word TRAINER are = 3 vowels.
The three vowels in the word TRAINER are A, I, and E.
Now these three vowels should always be together and these vowels can be in any order, but they should be together.
Here the three vowels AIE can be arranged in 3 factorial ways, as there are 3 vowels, as given below:
The number of ways the 3 vowels AIE can be arranged is = $3!$
Now arranging the consonants other than the vowels is given by:
As the left out letters in the word TRAINER are TRNR.
The total no. of consonants left out are = 4 consonants.
Now these 4 consonants can be arranged in the following way:
As in the 4 letters TRNR, the letter R is repeated for 2 times, hence the letters TRNR can be arranged in :
$ \Rightarrow \dfrac{{4!}}{{2!}}$
But the letters TRNR are arranged along with the vowels A,I,E, which should be together always but in any order.
Hence we consider the three vowels as a single letter, now TRNR along with AIE can be arranged in:
$ \Rightarrow \dfrac{{5!}}{{2!}}$
But here the vowels can be arranged in $3!$ as already discussed before.
Thus the word TRAINER can be arranged so that the vowels always come together are given below:
$ \Rightarrow \dfrac{{5!}}{{2!}} \times 3! = \dfrac{{120 \times 6}}{2}$
$ \Rightarrow 360$

The number of ways the word TRAINER can be arranged so that the vowels always come together are 360.

Note: Here while solving such kind of problems if there is any word of $n$ letters and a letter is repeating for $r$ times in it, then it can be arranged in $\dfrac{{n!}}{{r!}}$ number of ways. If there are many letters repeating for a distinct number of times, such as a word of $n$ letters and ${r_1}$ repeated items, ${r_2}$ repeated items,…….${r_k}$ repeated items, then it is arranged in $\dfrac{{n!}}{{{r_1}!{r_2}!......{r_k}!}}$ number of ways.

Q. In how many ways can the letter of the word "COMPUTER" be arranged so that 

All the vowels are always together.

The vowels may occupy only odd positions.

The relative position of vowels and consonants are not changed.

Solution:   

There are 8 different letters in the word 'COMPUTER' among them three are vowels and 5 are consonants. We want to arrange all the letters at a time such that:

a) All the vowels are always together.

It means that we cant arrange three vowels separately with 5 consonants. So, we assume 3 vowels as a single vowel with respect to 5 consonants. Thus, there are all together 6 letters and they can be arranged by 6! ways. But 3 vowels can be arranged to each other by 3! ways. Hence, By multiplication principle of counting:-

Total required ways = 6! * 3! = 4320

b) Vowels may occupy only an odd position.

Clearly, there are 4 odd positions and 3 vowels. Thus, 3 vowels can be arranged in 4 odd positions by P(4,3) ways. After arranging 3 vowels in an odd position, we arrange 5 consonants in the remaining 5 seats by 5! ways. Hence, By multiplication principle of counting:-

Total required ways = P(4,3) * 5! = 24*120 = 2880

c) Relative path of vowels and consonants are not changed.

It means, we can't arrange vowels and consonants separately but we arrange vowels with vowels and consonants with consonants. Thus, 5 consonants can be arranged by 5! ways, and 3 vowels can be arranged by 3! ways. Hence, By multiplication principle of counting:-

Total required ways = 5! * 3! = 720

Thus in this way, the word COMPUTER can be arranged if the above conditions are given.

7. In how many different ways can the letters of the word 'MATHEMATICS' be arranged such that the vowels must always come together?
A. 100020 B. 140020
C. 9800 D. 120960

Answer: Option D

Nội dung chính

  • How many ways can the letters in MATHEMATICS be arranged?
  • How many vowels are there in MATHEMATICS?
  • How many ways to arrange the letters in MATHEMATICS if the vowels are always together at the end of word?
  • How many arrangements can be made with the letters of the word MATHEMATICS order of vowels remains unchanged?
  • How many vowels are in the word computer?
  • How many different way can be formed by using all the letters of the word computer so that the vowels always come together?
  • How many ways can the letters of the word machine be arranged so that the vowels may occupy only the odd positions?
  • How many arrangements of the letters of the word computer are possible if they have co together in order?

Índice

  • Add Your Comment
  • How many ways can the letters in MATHEMATICS be arranged?
  • How many vowels are there in MATHEMATICS?
  • How many ways to arrange the letters in MATHEMATICS if the vowels are always together at the end of word?
  • How many arrangements can be made with the letters of the word MATHEMATICS order of vowels remains unchanged?

Explanation:

The word 'MATHEMATICS' has 11 letters. It has the vowels 'A','E','A','I' in it and these 4 vowels must always come together. Hence these 4 vowels can be grouped and considered as a single letter. That is, MTHMTCS(AEAI).

Hence we can assume total letters as 8. But in these 8 letters, 'M' occurs 2 times, 'T' occurs 2 times but rest of the letters are different.

Hence,number of ways to arrange these letters
$=\dfrac{8!}{(2!)(2!)}$ $=\dfrac{8×7×6×5×4×3×2×1}{(2×1)(2×1)}=10080$

In the 4 vowels (AEAI), 'A' occurs 2 times and rest of the vowels are different.

Number of ways to arrange these vowels among themselves $=\dfrac{4!}{2!}=\dfrac{4×3×2×1}{2×1}=12$

Hence, required number of ways
$=10080×12=120960$

kanchan

2015-10-22 10:47:46 

in how many times both T donot come together

jiju

2015-10-23 13:47:13 

to find that, remove both 'T's.  Then we have 9 letters out of which  'A' occurs 2 times  and 'M' occurs 2 times.
These can be arranged in 9!/(2!×2!)=90720 ways

Now there are 10 available positions and 2 positions can be selected from them in 10C2 = 45 ways

The two 'E's can be arranged in the selected 2 positions only in 1 way.

Therefore, number of arrangements where both 'T's do not come together = 90720 × 45
= 4082400

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Transcribed Image Text:In how many different ways can the letters of the word 'MATHEMATICS' be arranged such that the vowels must always come together? * 9800 O 100020 O 140020 O 120960

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How many ways can the letters in MATHEMATICS be arranged?

There are 24 different ways to arrage the letters in the word math .

How many vowels are there in MATHEMATICS?

In the word 'Mathematics', we treat the vowels A, E, A, I as one letter. Thus, we have MTHMTCS (AEAI). Now, we have to arrange letters, out of which M occurs twice, T occurs twice, and the rest are different. Now, vowels A, E, I, A, has 4 letters in which A occurs 2 times and rest are different.

How many ways to arrange the letters in MATHEMATICS if the vowels are always together at the end of word?

120960 ways . Originally Answered: In how many different ways can the letters of the word mathematics be arranged so that the vowels always come together?

How many arrangements can be made with the letters of the word MATHEMATICS order of vowels remains unchanged?

The answer is 10,080 ways.

How many vowels are in the word computer?

There are 3 vowels and 6(5 consonant units + 1 vowel unit) objects that can be rearranged.

How many different way can be formed by using all the letters of the word computer so that the vowels always come together?

Solution(By Examveda Team) The given word contains 8 different letters. We keep the vowels (OAE) together and treat them as 1 letter. The vowels (OAE) can be arranged among themselves in 3! = 6 ways.

How many ways can the letters of the word machine be arranged so that the vowels may occupy only the odd positions?

Required number of ways = (360 * 2) = 720. In how many different ways can the letters of the word 'MACHINE' be arranged so that the vowels may occupy only the odd positions ? Now, 3 vowels can be placed at any of the three places, out of the four marked 1, 3, 5,7.

How many arrangements of the letters of the word computer are possible if they have co together in order?

a. All the eight letters in the word COMPUTER are distinct, so the number of ways in which we can arrange the letters equals the number of permutations of a set of eight elements. This equals 8! = 40,320.

How many vowels are in the word computer?

In the given word, there are 3 vowels O, U, and E which will be treated as 1 unit.

How many ways can the letters in the word computer be arranged if the letters CO must remain next to each other in order as a unit?

c. When the letters are arranged randomly in a row, the total number of arrangements is 40,320 by part (a), and the number of arrangements with the letters CO next to each other (in order) as a unit is 5,040.

How many ways can you arrange the vowels?

The vowels (EAI) can be arranged among themselves in 3! = 6 ways. Required number of ways = (120 x 6) = 720.

How many ways can the letters of the word machine be arranged so that the vowels may occupy only the odd positions?

Required number of ways = (360 * 2) = 720. In how many different ways can the letters of the word 'MACHINE' be arranged so that the vowels may occupy only the odd positions ? Now, 3 vowels can be placed at any of the three places, out of the four marked 1, 3, 5,7.