A die is loaded in such a way that an even number is twice as likely to occur as an odd number
A die is loaded in such a way that each odd number is twice as likely to occur as each even number. Find P(G), where G is the event that a number greater than 3 occurs on a single roll of the die. Show
A die is loaded in such a way that each odd number is twice as likely to occur as each even number. Find P(G), where G is the event that a number greater than 3 occurs on a single roll of the die. Solution: The
probability of odd numbers Get the answer to your homework problem. Try Numerade free for 7 days We don’t have your requested question, but here is a suggested video that might help. Related QuestionA die is loaded in such a way that an even number is twice as likely to occur as an odd number: If E is the event that & number less than 4 occurs on a single toss of the die, find P(E). Select one; 5/8 6/9 3/6 4/7 DiscussionYou must be signed in to discuss. Video Transcriptin this question, we are given that a dye is loaded in such a way that an even number is twice as likely to occur as an odd number. Now we know that a die is going to have these Numbers. 1, 2, 3, 4, 5 up to six. And the probability of having an even number, we are going to call it X. And the probability of having an odd number, we're going to call it. Why? Now? We are given that the probability of an even number X is twice the probability of odd number. Why? So we have a question one. And secondly we know that for this day we have our even numbers they said to four and six in our own numbers As he said one, three and five. No, We know that the probability of these numbers should add up to one if we throw a die once. So the probability of having probability of having any number that is That gives us one is equal to the probability Of it being a one Plus the probability of it being a two plus probability of it being a three plus. The probability of it being a four plus, the probability of it being a five plus lastly the probability of it being a six. Now again here we know that the probability of an odd number is we have called it. Why? So here we have Why? Plus X. Plus why? Plus this will be Y. X. Y. X. Plus why? Plus X. So and it gives us a one. So we have another equation with three X plus three Y is equal to one. So we'll call this equation to. Now solving these two equations three X plus three Y is equal to one and X is equal to two Y. Now replacing X by two I we have three by two. Y plus three Y is equal to one. Here we have six Y plus three Y Is equal to one. nine Y is equal to one and why is equal to 1/9. Therefore X which is two, Y is equal to 2/9. Now our question the event, the probability of having a number that is less than four, That is less than four is equal to the probability of it being a one plus The probability of it being a two Plus the probability of it being a three. And here we now know that the probabilities the probability of it being an odd number is 1/9 plus 2/9 plus 1/9. And therefore we get, our final answer is 4/9 which is not there on our given answers. And the question is um the options that are given, there's no right answer the correct answer is for overnight. Please contact your instructor. Thank you
+0 A die is loaded in such a way that an even number is twice as likely to occur as an odd number.0 7 3913 1 A die is loaded in such a way that an even number is twice as likely to occur as an odd number. If E is the event that a number less than 4 occurs on a single toss of the die, find P(E). Guest Feb 29, 2020 0 users composing answers..1+0 Answers#1 +6236+1 \(P[E]=2P[O]\\ P[E]+P[O]=1\\ P[E]=\dfrac 2 3,~P[O]=\dfrac 1 3\\ P[1]=P[3]=P[5]=\dfrac 1 3 \cdot \dfrac 1 3 =\dfrac 1 9\\ P[2]=P[4]=P[6]=\dfrac 1 3 \cdot \dfrac 2 3 = \dfrac 2 9\\ P[roll < 4]=P[1]+P[2]+P[3] = \dfrac 1 9 + \dfrac 2 9 + \dfrac 1 9 = \dfrac 4 9\) .Rom Mar 1, 2020 12 Online UsersTop Users+117821 Melody moderator +33149 Alan moderator +13883 asinus moderator +9445 hectictar +3769 Probolobo +3122 admin administrator+2971 TitaniumRome +2437 BuilderBoi +2396 GingerAle +1975 saseflower +1224 CubeyThePenguinSticky TopicsSome guidelines for question askers. What is Happening 5 Again a number puzzle. Multiply in writing. Loads of fun printable number and logic puzzles ¤¤¤¤Welcome To Web2.0calc¤¤¤¤ How to display latex properly Feature Questions 1 - Started 8th May 19 How to upload a picture. If a question is ticked that does not mean you cannot continue it. Should you consider anything before you answer a question? Geometry Thread PUZZLES LaTex Coding https://www.desmos.com/calculator/bsh9ex1zxj Historical post! What is happening? Wrap #4 Great Questions to Learn From 2 Great Answers to Learn From Reference Material Information for new people. What is the probability of rolling an even number on a die twice?1 Expert Answer
Each roll of the dice is an independent event. The probability of a 1 on one roll is 1/6 and the probability of an even number on the second roll is 3/6 = 1/2.
What is the chance of landing on an even number when you throw a die?The probability of rolling an even number is three out of six, or three-sixths. This fraction can be simplified as the numerator and denominator are both divisible by three. Three divided by three is equal to one, and six divided by three is equal to two. This means that the answer, in its simplest form, is one-half.
How many ways are there in getting an even number when a die rolled?
What is the chance that an odd number appears when you throw of die?And there is six possible outcomes, the numbers one to six. The probability when rolling a regular six-sided dice that the score is an odd number is three-sixths or three out of six.
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